-sin(4x-5)+cos(x^2)=0

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Solution for -sin(4x-5)+cos(x^2)=0 equation:


Simplifying
-1sin(4x + -5) + cos(x2) = 0

Reorder the terms:
-1ins(-5 + 4x) + cos(x2) = 0
(-5 * -1ins + 4x * -1ins) + cos(x2) = 0
(5ins + -4insx) + cos(x2) = 0

Multiply cos * x2
5ins + -4insx + cosx2 = 0

Reorder the terms:
cosx2 + 5ins + -4insx = 0

Solving
cosx2 + 5ins + -4insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5ins' to each side of the equation.
cosx2 + 5ins + -5ins + -4insx = 0 + -5ins

Combine like terms: 5ins + -5ins = 0
cosx2 + 0 + -4insx = 0 + -5ins
cosx2 + -4insx = 0 + -5ins
Remove the zero:
cosx2 + -4insx = -5ins

Add '4insx' to each side of the equation.
cosx2 + -4insx + 4insx = -5ins + 4insx

Combine like terms: -4insx + 4insx = 0
cosx2 + 0 = -5ins + 4insx
cosx2 = -5ins + 4insx

Divide each side by 'osx2'.
c = -5ino-1x-2 + 4ino-1x-1

Simplifying
c = -5ino-1x-2 + 4ino-1x-1

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